A phone call to the service ce
A phone call to the service center has a normal distributionwith mean 10 min and standard deviation 2 min. During one day therewere 5 phone calls and during the other day there were 6 calls.What is the probability that the sample average taken on each ofthe two days is at most 11?
Answer:
Solution :
Given that ,
mean = 
= 10
standard deviation = 
= 2
n = 6
= 10
= / 
n = 2 / 6
P(> 11) = 1 – P(< )
= 1 – P[(– ) / < (11 – 10) / 2 / 6 ]
= 1 – P(z < 1.22)
= 1 – 0.8888
= 0.1112
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