# A phone call to the service ce

A phone call to the service center has a normal distributionwith mean 10 min and standard deviation 2 min. During one day therewere 5 phone calls and during the other day there were 6 calls.What is the probability that the sample average taken on each ofthe two days is at most 11?

Solution :

Given that ,

mean = = 10

standard deviation = = 2

n = 6

= 10

= / n = 2 / 6

P(> 11) = 1 – P(< )

= 1 – P[() / < (11 – 10) / 2 / 6  ]

= 1 – P(z < 1.22)

= 1 – 0.8888

= 0.1112

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