A solid mixture consists of 39
A solid mixture consists of 39.1 g of KNO3 (potassium nitrate)and 6.9 g of K2SO4 (potassium sulfate). The mixture is added to130. g of water.
A. Consider the mixture described in the introduction. At 60 ∘C, to what extent will each solute be dissolved? (Totallydissolved, partially dissolved, not dissolved)
B. If the solution is cooled to 0 degrees Celsius, what mass,in grams, would KNO3 crystallize?
Answer:
initially solid mixture has
mass of KNO3 = 39.1 g
mass of K2SO4 = 6.9 g
total mixture added to 130 g of water
from the graph , solubility of K2SO4 in water at 60oC is = (18 /100 ) x 130
= 23.4 g K2SO4
23.4 g K2SO4 > 6.9 g of K2SO4.
so total K2SO4 is completely dissolved
from the graph , solubility of KNO3 in water at 60oC is = (50 /100 ) x 130
= 65 g KNO3
65 g KNO3 > 39.1 g of KNO3.
so total KNO3 is completely dissolved
B)
from the graph , solubility of KNO3 in water at 0oC is = (15 /100) x 130
= 19.5 g KNO3
we have 39.1 g KNO3 . but soluble is 19.5 g KNO3. so remainingwill form crystalls
mass of KNO3 crystallized = 39.1 – 19.5 = 19.6 gKNO3
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