For each reaction, calculate Δ
For each reaction, calculate Δ H ∘ rxn , Δ S ∘ rxn , and Δ G rxnat 29 ∘ C .
A) N2O4(g)→2NO2(g)
B) NH4Cl(s)→HCl(g)+NH3(g)
C)3H2(g)+Fe2O3(s)→2Fe(s)+3H2O(g)
D) N2(g)+3H2(g)→2NH3(g)
Answer:
For each reaction,
A) dHorxn = dHo(products) – dHo(reactants)
= 2 x 33.2 – 9.1 = 57.3 kJ/mol
dSorxn = dSo(products) – dSo(reactants)
= 2 x 240 – 304 = 176 J/K.mol
T = 29 + 273 = 302 K
dGorxn = dHorxn – TdSorxn
= 4.15 kJ/mol
B) dHorxn = dHo(products) – dHo(reactants)
= -92.3 – 45.9 – (-314.6) = 176.4 kJ/mol
dSorxn = dSo(products) – dSo(reactants)
= 186.9 + 192.8 – 94.8 = 284.9 J/K.mol
T = 29 + 273 = 302 K
dGorxn = dHorxn – TdSorxn
= 90.36 kJ/mol
C) dHorxn = dHo(products) – dHo(reactants)
= 3 x -241.8 – (-824.2) = 98.8 kJ/mol
dSorxn = dSo(products) – dSo(reactants)
= (2 x 27.3 + 3 x 189) – (3 x 130.7 + 87.4) = 142.1 J/K.mol
T = 29 + 273 = 302 K
dGorxn = dHorxn – TdSorxn
= 55.92 kJ/mol
D) dHorxn = dHo(products) – dHo(reactants)
= 2 x -45.9 = -91.8 kJ/mol
dSorxn = dSo(products) – dSo(reactants)
= 2 x 192.8 – (191.6 + 3 x 130.7) = -198.1 J/K.mol
T = 29 + 273 = 302 K
dGorxn = dHorxn – TdSorxn
= -32.00 kJ/mol
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