The reaction of CH3OH(g) with
The reaction of CH3OH(g) with N2(g) to give HCN(g), NH3(g), andO2(g) requires 164 kJ/mol of CH3OH(g).
a) Write a balanced chemical equation for this reaction. Includethe phases of all species in the reaction.
b)Should the thermal energy involved be written as a reactant oras a product?
c) How much heat is involved in the reaction of 70.0 g ofCH3OH(g) with excess N2(g) to give HCN(g) and NH3(g) in thisreaction?
Answer:
(a) Balanced chemical equation is:
2 CH3OH(g) + 2N2(g) + 164kj 
2HCN(g)+ 2NH3 +O2(g)
(b) The thermal energy here is energy absorbed for every mole ofmethanol hence it should be written with reactants.
(c) since 1 mole of methanol absorbs 164kj of heat
1mol of methanol= 32g =164kj of heat
1g of methanol will absorb 164/32 kj of heat
70 g of methanol will absorb= 164/32*70 kj of heat
= 358.75kj
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