What are the balanced reaction

What are the balanced reaction equations for:

1.0 M lead (II) nitrate and Zn

0.1 M lead (II) nitrate and Zn

1.0 M copper nitrate and Mg

1.0 M potassium nitrate and Mg

1.0 M copper nitrate and Pb

1.0 M copper nitrate and Zn

0.1 M iron sulfate and Mg

0.1 M copper nitrate and Zn

Answer:

This is done via activity of better yet, with reductinopotentials:

Zn2+ + 2 e− ⇌ Zn(s) −0.7618;

Pb2+ + 2 e− ⇌ Pb(s) −0.126;

Cu2+ + 2 e− ⇌ Cu(s) +0.337;

Mg2+ + 2 e− ⇌ Mg(s) −2.372;

Fe2+ + 2 e− ⇌ Fe(s) −0.44

then

1.0 M lead (II) nitrate and Zn –> Pb(NO3)2 + Zn(s) –>Zn(NO3)2 + Pb(s); since Pb > Zn potential

0.1 M lead (II) nitrate and Zn –> Pb(NO3)2 + Zn(s) –>Zn(NO3)2 + Pb(s); since Pb > Zn potential

1.0 M copper nitrate and Mg –> Cu(NO3) + Mg(s) –> Cu(s)+ Mg(NO3)2, since Mg < Cu, reduciton potential

1.0 M potassium nitrate and Mg –> no reaction, K+ remainsaquoeus

1.0 M copper nitrate and Pb –> Cu(NO3)2 + Pb –> Cu(s) +Pb(NO3)2, since CU > Pb

1.0 M copper nitrate and Zn –> Cu(NO3)2 + Zn -> Zn(NO3)2+ Cu(s) , since CU > Zn

0.1 M iron sulfate and Mg –> FeSO4 + Mg –> MgSO4 +Fe+2

0.1 M copper nitrate and Zn –> Cu(NO3)2 + Zn –> Zn(NO3)2+ Cu(s) since Cu > Zn


 
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